This page is for students who have wrestled with some problems involving the Gibbs equation, ΔG = ΔH - TΔS, and think that the DH in it has nothing to do with entropy.
Prof: The whole Gibbs relationship or function is about entropy change.
Student: Youre wrong. Just that last term, TΔS, is entropy change. Theres always a conflict between the enthalpy and the entropy terms. Only at high temperatures does the entropy part win. Ha.
P: Divide the Gibbs deal by T. Whats the nature of the terms now? Doesn't each one look like entropy change?
S:Δ G/T = Δ H/T - Δ S. Whaddya mean, look like entropy change? Δ S is q/T.
P: Sure, but q is the transfer of thermal energy (that we often, too loosely, call "heat"). So isntΔH really a "q", a thermal energy transfer? Also, ΔG/T has the form of an energy transfer/T just as that ΔH/T does. All ΔSs! Therefore, the Gibbs equation really is
"Entropy change (1) = Entropy change (2) Entropy change (3)"
BUT wed better be a lot more specific and talk about what those three entropy changes really mean.
S: Darn right. Divide by T and I admit everything in that Gibbs looks like entropy change. But that just confuses me. What happens to the fight between enthalpy and entropy if enthalpy turns into entropy? Do I have to learn another mysterious phys chem equation?
P: No way, no mystery. Lets give it the full court press youll be amazed at how neat everything comes out (because now that "fight" between enthalpy and entropy will make sense). It'll give you a much better feel for entropy itself.
To start, lets think about a system in which a chemical reaction is occurring. There can be thermal energy transferred ("heat") from the system to its surroundings or vice versa. Well, lets really think big by saying that nothing else is happening in the entire universe but the reaction in our system. Look at the entropy changes involved:
Now, if chemicals are mixed in the system (at constant T and, normally, constant P) and a reaction occurs, some thermal energy transfer ("heat"), q, takes place in the reaction. How much q? That's easy: q is the change in enthalpy; q =ΔH(system). (The sign of ΔH can be + or - , but we're just talking broadly and generally, so let's start simply with + ΔH.)
However, from the viewpoint of the surroundings, the sign ofΔH changes when thermal energy is transferred from the system and becomes absorbed by the surroundings, i.e., a + ΔH(system) when transferred to the surroundings becomes - ΔH(surroundings) -- (and, of course, a -ΔH(system) when transferred out of the system becomes ΔH(surroundings). As a general equation, simply to express that change of sign, here's (2):
-ΔH(surroundings) =ΔH(system) (2)
What does this have to do with entropy? To answer that, lets divide equation (2) by T:
-ΔH/T(surroundings) = ΔH/T(system) (3)
Then, sinceΔS = q/T, and the only q in the surroundings right now is - ΔH, that means that - ΔH/T(surroundings) = - ΔS(surroundings). Therefore, inserting this result in equat. (3):
(Assuming that the surroundings are far larger than the system, i.e., reversible conditions.)
-ΔS(surroundings) = ΔH/T(system) (4)
or, changing signs merely so we have a +ΔS to work with in a moment,
Now, replacingDS(surroundings) in equat. (1) with -ΔH/T(system) as just justified by (5):
ΔS(universe) = - ΔH/T(system) + ΔS(system) (6) ΔS(universe)?? Just to say that aloud seems like a really big mouthful -- and head-full! But remember that we started out originally by saying that the only reaction happening in the whole universe was the one in our constant T, constant P system. So any DS(universe) would be perfectly measured by what happens only in our system.
Let's see. To put it in the most general terms, the energy change that occurred in the reaction in the system -- and which entropy measures byΔS = q/T -- has been spread out, some remaining in the system as ΔS and some being transferred to the surroundings and identifiable as the ΔH/T(surroundings). (It can be used for work, but right now we're looking at it either as though it was all dissipated as unavailable thermal energy or as though the work itself had resulted in the same amount of waste energy, i.e., as ΔS(surroundings).
But exactly what was the original energy change that came out of the reaction in our system? We don't know, but let's give it a symbol ofΔG(system). OK, since that was the only event that occurred in the universe, and because energy flow (thermal energy transfer, "heat") divided by T is entropy, ΔG/T(system) is equal to the total entropy change in the entire universe due to this reaction! ΔS(universe) = ΔG/T(system)
Oops! Watch it! We have to switch algebraic signs when looking at this energy/T change from a universe's viewpoint rather than from the system's. So
and equation (6) -- derived from that "way-back-there" equation (1) -- becomes
-ΔG/T(system) = - ΔH/T(system) + ΔS(system)
Multiply through by T and what do you get?
S: How about that! The old Gibbs, ΔG = ΔH - TΔS. But wait. What kind of fast shuffle are you dealing me when you to start with all entropy and end up with enthalpy and ΔG thats called "free energy"? Is entropy enthalpy? Is entropy free energy? Im REALLY confused now.
P: Slow down. Dont panic.
Entropy is never enthalpy, nor free energy. A systems enthalpy is only entropy change (after ΔH is divided by T) if it is transferred to the surroundings and no work of any sort is done there in the surroundings. A surroundings enthalpy is only entropy change (after ΔH being divided by T) when it is transferred to the system and no work is then performed in the system. Gibbs free energy change, ΔG, is only considered entropy change(after being divided by T) when no useful work of any kind is done by the heat transfer in the system or in the surroundings.
Starting with that Equation (1), we have found the breadth of the concept we call entropy. Entropy change, in the classical "macrothermodynamics" we've been looking at, is the ratio-measure, q/T, of the driving force for every spontaneous chemical reaction in the universe. Even when we focus on a little chemical system in our lab on earth by means of the Gibbs equation, we see the driving force -- the tendency of energy formerly bound in reactants to be spread out in the products. From information in other areas of chemistry than thermodynamics, we now know that theΔH of Gibbs primarily comes from the difference in electronic binding energy between products and reactants. Usually in exothermic reactions, the products have stronger bonds and so some of the greater binding energy in the less strongly bound reactants is released as heat. From the energetics of molecules (again, outside of macrothermodynamics) we know that this increased thermal energy is due to molecules moving more rapidly and colliding more forcefully with one another. When the resultant DH(system) gets to the surroundings, it can be used to boil water or run a steam engine or charge a battery. But if it isnt used for doing any work, it is simply dissipated in the surroundings as DH/T(surroundings), i.e., as ΔS(surroundings). It becomes entropic "waste heat", no longer capable of causing change because it is at the same temperature as the surrondings (even though it may have raised the terperature of the surroundings and infinitesimal amount.)
The Gibbs equation is only concerned with macrothermodynamics, with what we can measure in the lab rather than what is happening down there inside the molecules during chemical reactions. What IS entropy change from the viewpoint of a molecule? Boltzmann and "microthermodynamics" deal with that. (You've heard a lot about it in other sections of this Web site.) To begin with, depending on their temperature and solid/liquid/gas state, all molecules need a certain amount of energy to move and rotate and vibrate internally, in addition to the large amount of electronic energy in their bonds that holds them together. S(298oK, formation) in your textbook tables -- that's reallyDS(from absolute zero, formation) because entropies are assumed to be 0 there -- measures all those kinds of energy "in a bundle". So TΔS in the Gibbs equation is the amount of energy a mol of product molecules needs to exist at a temperature T compared to one of reactant molecules. (Give them more energy and they scoot around faster because the added energy goes into their translational/rotational/ vibrational modes. Heat them up to a high enough temperature and you even boost them to an excited electronic state where bond breaking can occur.
The confusion -- about "If it's enthalpy, how can that be entropy???" -- comes in because the BIG equation (1) is actually the ultimate scenario for energy transfer in any chemical change. (Or "physical change" too, but let's skip that in concentrating on Gibbs.) We may be able to sneak some work out of theΔH when or as that energy transfer from system to surroundings occurs and that's fine. Perhaps we can use it for human purposes. Good. Go ahead and calculate how much w.
But equation (1) is saying that ultimately any kind of work is going to become diffused (or at least tend to) and will then be unusable dispersed thermal energy in just as many molecules in the system and surroundings as possible. Entropy measures energy transfers from "concentrated" to "spread out", and that's the overall trend in the physical universe.
So you now have a better picture of fundamentals and of the Gibbs equation. There is no "conflict" betweenΔS. They're really just different aspects of entropy change: ΔH will become entropy in the surroundings if it does no work, and TΔS just represents what little energy is left over to become dissipated (as increased entropy in the surroundings) after the ΔS(formation) of the product molecules has been taken care of.
S: Ho ho ho! Now I see better what that "crossover T" point in the problems I worked really means. At low temperatures many reactions, say the old one of water being broken into hydrogen and oxygen gas, just don't go to any appreciable extent. Why not? Well, you simply don't have enough energy around in the system to put it into any new hydrogen and oxygen molecules so they can exist with their own individual allotments ofΔS even in their minimal quantum levels. However, as you raise the temperature more and more from outside the system -- and that means more and more intense energy, not just more energy -- there comes a temp point where you have enough flowing into the system to give the H2 and O2 molecules adequate energy for them to exist. Then any temperature above that is more than they need: they show it by flying around faster and hitting each other harder and harder.
Entropy is the key, especially when I can see it interpreted by what you call "microthermodynamics". That micro stuff says that entropy measures how much energy is needed to fill those many more electronic (plus vibrational, etc.) quantum levels in the hydrogen and oxygen compared to the water. Neat. If there's not enough intense energy to fill them? Forget it. No reaction. Even though the text's talking about "positional entropy" and "the more molecules, the more entropy" made it easy to answer questions about increased entropy, I never could see how having more molecules in the products than the reactants had anything to do with the reaction not going at low T and going at high T.
P: Hooray. Ya got it.
Scholarly and helpful analysis of the Gibbs function, showing that is is more closely related to entropy than to energy and building on Plancks function (of total entropy change in a universe) that is used in this Web page: Professor Laurence E. Strong and H. Frank Halliwell, Journal of Chemical Education, 1970, 47  347 352.
An excellent introduction to Professor Norman C. Craigs procedure of attacking entropy problems and to his short book Entropy Analysis (John Wiley, New York 1992), the best text on the subject, is in "Entropy Analyses of Four Familiar Processes", Journal of Chemical Education, 1988 65 (9), 760 764.
Professor John P. Lowes explanation of the importance of the occupancy of energy levels as a genuine basis for entropy (rather than "randomness" or "disorder") via Q and A is superb in Journal of Chemical Education, 1988 65 (5), 403 406.
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